(2/w-3)-(2/w+3)=12/w^2-9

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Solution for (2/w-3)-(2/w+3)=12/w^2-9 equation: 


D( w )

w^2 = 0

w = 0

w^2 = 0

w^2 = 0

1*w^2 = 0 // : 1

w^2 = 0

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

2/w-(2/w)-3-3 = 12/(w^2)-9 // - 12/(w^2)-9

2/w-(2/w)-(12/(w^2))-3-3+9 = 0

2/w-2*w^-1-12*w^-2-3-3+9 = 0

-12*w^-2 = -3 // : -12

w^-2 = 1/4

-2 < 0

1/(w^2) = 1/4 // * w^2

1 = 1/4*w^2 // : 1/4

4 = w^2

w^2 = 4 // ^ 1/2

abs(w) = 2

w = 2 or w = -2

w in { 2, -2 }

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